F(x)=12-x+2x^2-4x

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Solution for F(x)=12-x+2x^2-4x equation: 



(F)=12-F+2F^2-4F

We move all terms to the left:

(F)-(12-F+2F^2-4F)=0

We get rid of parentheses

-2F^2+F+4F+F-12=0

We add all the numbers together, and all the variables

-2F^2+6F-12=0

a = -2; b = 6; c = -12;
Δ = b2-4ac
Δ = 62-4·(-2)·(-12)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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